t^2-t-300=0

Solution for t^2-t-300=0 equation:

t^2-t-300=0

We add all the numbers together, and all the variables

t^2-1t-300=0

a = 1; b = -1; c = -300;
Δ = b2-4ac
Δ = -12-4·1·(-300)
Δ = 1201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{1201}}{2*1}=\frac{1-\sqrt{1201}}{2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{1201}}{2*1}=\frac{1+\sqrt{1201}}{2}
$